Comments for Site Grammar

Comment on Selenium IDE Arrays by John M

John M — Wed, 30 Nov 2022 10:55:33 +0000

Good morning,
Is it possible to have a multidimensional array in selenium ide? I want to pass multiple values into a page on a web application and then do an assert against a calculation on the next page. So for example on page 1, I might want to pass 1 and 2, and assert that on the next page, the answer is 3. I’ll have hundreds of these combinations so I’d like my array to have rows of aval1, Val2 and then the desired result.

Comment on Selenium IDE Arrays by nam

nam — Tue, 05 Jul 2022 05:25:25 +0000

In reply to christophertangalin@gmail.com. I've been trying to solve this issue for 2 days. Thank you!

Comment on Selenium IDE Arrays by christophertangalin@gmail.com

christophertangalin@gmail.com — Tue, 15 Feb 2022 16:23:01 +0000

In reply to Ileana.

Hi Ileana,

You can use locators to find a specific element on a page. Read more about locators here:
https://www.guru99.com/locators-in-selenium-ide.html
https://www.javatpoint.com/selenium-ide-locating-strategies

Once you’ve located the element you would have to figure out a way to access the other element on the same row. How do you decide which element should be accessed? Are there any rules to determine the final element to be accessed (e.g. the element three columns to the left of the initially searched-for element)?

Comment on Selenium IDE Arrays by Ileana

Ileana — Tue, 15 Feb 2022 13:52:12 +0000

Hi! nice article! I would like to ask about a problem I am facing: I need to search for an especific element in a column of a table in a web page, and then access another element in the same row but different column. Is there a way to do that? I had found the command “storeElementIndex”, but it seems to be deprecated. Thanks in advance for your help!

Comment on Selenium IDE Arrays by christophertangalin@gmail.com

christophertangalin@gmail.com — Thu, 20 Jan 2022 10:23:05 +0000

In reply to Robert Packer. Glad I could help, cheers!

Comment on Selenium IDE Arrays by Robert Packer

Robert Packer — Thu, 20 Jan 2022 01:21:31 +0000

In reply to christophertangalin@gmail.com. That was a lot of help! Thank you so much.

Comment on Selenium IDE Arrays by christophertangalin@gmail.com

christophertangalin@gmail.com — Tue, 18 Jan 2022 13:52:22 +0000

In reply to Robert Packer. Yes, it is possible! Here's one way to loop through every single link on a page using the document.links property. You can access each URL using the href value. In the example below, I'm echoing every link on Google's homepage. Let me know if this helped.

Comment on Selenium IDE Arrays by Robert Packer

Robert Packer — Mon, 17 Jan 2022 19:58:00 +0000

Is it possible to loop through one or more links on a page? The ID’s are never the same but I guess that’s another issue.

Comment on Selenium IDE Arrays by christophertangalin@gmail.com

christophertangalin@gmail.com — Wed, 29 Sep 2021 10:26:32 +0000

In reply to Tim.

Hi Tim, are you trying to capture the element value or the element index?

Perhaps a counter could be used to keep track of the last created element?

I’m not sure that I understand your problem correctly though. Would you mind sharing a screenshot of the code in Selenium IDE? You can also send your .ide file to christophertangalin@gmail.com and I will have a look at it.

Comment on Selenium IDE Arrays by Tim

Tim — Wed, 29 Sep 2021 10:05:48 +0000

Good afternoon. Please tell me how to catch the last created element using the Selenium IDE:

type
name = name
New Division

clickAndWait
css = # form-add> input.btn.btn-primary

assertValue
// input [@ name = ’roles [362] [name]’]
New Division

When adding a new element, the locator for it is created on the basis of +1
that is, only the numerical value changes.
For xpath it looks like this: // input [@ name = ’roles [362] [name]’] the next element created will have xpath // input [@ name = ’roles [363] [name]’]
Actually the question is: how to catch the last created element, which is the element with the maximum chill value?
I would be very grateful if you can help me figure it out.